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Topic: Finding concentration  (Read 3005 times)

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Offline Rookie

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Finding concentration
« on: April 25, 2007, 09:17:06 PM »
I am told that there are 3.0 mL of 0.1 M of AgNO3 and 3.0 mL of 1 M NH3... and they're asking me to find the concentration of Ag(NH3)22+
So, first i wrote a balanced reaction:
Ag(NH3)2 --> 2NH3 + Ag

Then i figured that it goes by stoichiometry so i took Ag+ and wrote:

0.003L * (0.1 mol Ag / 1L Ag) + (1 mol Ag(NH3)2/ 1 mol Ag)
But, now what? and am i actually doing this right?

Offline lemonoman

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Re: Finding concentration
« Reply #1 on: April 25, 2007, 11:57:08 PM »
I am told that there are 3.0 mL of 0.1 M of AgNO3 and 3.0 mL of 1 M NH3... and they're asking me to find the concentration of Ag(NH3)22+
So, first i wrote a balanced reaction:
Ag(NH3)2 --> 2NH3 + Ag

Then i figured that it goes by stoichiometry so i took Ag+ and wrote:

0.003L * (0.1 mol Ag / 1L Ag) + (1 mol Ag(NH3)2/ 1 mol Ag)
But, now what? and am i actually doing this right?

Something's wrong with your question.

You talk about AgNO3 mixed with NH3, and they ask for Ag(NH3)22+ ?   Are you sure?

Offline Borek

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Re: Finding concentration
« Reply #2 on: April 26, 2007, 02:41:54 AM »
Assuming 2+ is just a typo - this is either simple stoichiometry question (you assume all Ag+ reacted) or equilibrium question (you need to find complex formation constant). In the latter case something lice ICE table could be helpfull.
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