Ok, so I would have .007 mols of product ==> .007 mols of my limiting reagent

.007 mol x 138 g/mol = .966 g

Then 1.10 g of my actual limiting reagent / .966 g = 113 % yield (is it possible to have >100% yield??)

Erm.. not sure if I did it correctly

No. Tell me your secret. 113 % yield?

You said you have 1.10 g of salicyclic acid, we'll denote as "SA." You also said your product, acetylsalicylic acid (ASA) was 1.26 g.

According to your molecular weights, which I'm too tired to check, this means you have

**0.0079710** moles of SA (not 0.007), your limiting reagent. I have not rounded this number yet. Do this

last in any calculation.

So if this is how many moles of limiting reagent you have, this must mean you have 0.0079710 moles of ASA as well, your product. You can convert this to grams.

A percent yield calculation is simply

actual amount **x** 100

theoretical amount

You just calculated your theoretical amount of ASA. Your actual was 1.26 g. You have a percent now, which is might I say quite good, 87.8 % .