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Topic: solubility equilibrium  (Read 2601 times)

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Offline yazz

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solubility equilibrium
« on: June 10, 2007, 09:37:05 PM »
ksp=3.7*10*-15 for AlOH3. A precipitate just began to form when 50.0ml of 2.0*10*-6M of AlOH3 was mixed with 50ml of NaOH solution. What was the concentration of the NaOH solution?

AlOH3= Al + 3OH
3.7*10*-15/2.0*10*-6=3OH
OH=6.1*10*-10 M

i don't know whether this is the way to do it or not. please help

Offline Yggdrasil

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Re: solubility equilibrium
« Reply #1 on: June 10, 2007, 10:07:13 PM »
You're on the right track, but your answer is incorrect.  First, what is the concentration of aluminum ions in your final solution (hint: it's not 2x10-6M).  Second, it would be beneficial to write out the equation for Ksp in terms of [Al3+] and [OH-].  This may help you find the correct [OH-].

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