Ok, mitch. This is my second attempt on this conundrum:

a) For Cd+2, there are 46 electrons (Cd has an atomic number of 48).

Electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d8

Since Cd has a +2 charge, its coordination number is 4. Therefore, it can accommodate 4 electron pairs. The empty orbitals are one 4d orbital and three 5p orbitals.

b) For Ag+, there are 46 electrons (Ag has an atomic number of 47).

Electronic configuration: 1s2 2s2 2p6 3s2 2p6 4s2 3d10 4p6 5s2 4d8

Since Ag has a +1 charge, its coordination number is 2. Therefore, it can accommodate 2 electron pairs. The empty orbitals are one 4d orbital and one 5p orbital.

c) For Ce+3, there are 55 electrons (Ce has an atomic number of 58).

Electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d10 5p6 6s1

Since Ce has a +3 charge, its coordination number is 6. Therefore, it can accommodate 6 electron pairs. The empty orbitals are six 4f orbitals.

d) For Fe+2, there are 24 electrons (Fe has an atomic number of 26).

Electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d4

Since Fe has a +2 charge, its coordination number is 4. Therefore, it can accommodate 4 electron pairs. The empty orbitals are three 3d orbitals and one 4p orbital.

e) For Mn+2, there are 23 electrons (Mn has an atomic number of 25).

Electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d3

Since Mn has a +2 charge, its coordination number is 4. Therefore, it can accommodate 4 electron pairs. The empty orbitals are three 3d orbitals and one 4p orbital.

f) For Zn+2, there are 28 electrons (Zn has an atomic number of 30).

Electronic configuration: 1s2 2s2 2p6 3s2 3p6 4s2 3d8

Since Zn has a +2 charge, its coordination number is 4. Therefore, it can accommodate 4 electron pairs. The empty orbitals are one 3d orbital and three 4p orbitals.

I would appreciate any replies from you guys. Am I on the right track? Thank you.

Sincerely,

Tashkent