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Offline rannekk

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problem regarding moles...
« on: June 26, 2007, 07:41:49 AM »
Greetings!
I could use some help with this question:
3.40g of CaSO4 (M=136g mol-1) is formed when 4.30g of hydrated calcium sulfate is heated to constant mass. How many moles of water of crystallisation are combined with each mole of calcium sulfate?

A: 1
B: 2
C: 3
D: 4

.. I have been baffled with this question, not knowing where I am supposed to start. ??? ???

Cheers

Offline Borek

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Re: problem regarding moles...
« Reply #1 on: June 26, 2007, 08:26:23 AM »
How many moles of CaSO4 was left? How much water was lost? How many moles of water were lost?
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Offline rannekk

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Re: problem regarding moles...
« Reply #2 on: June 26, 2007, 08:38:11 AM »
0.500mol water lost 0.0250mol CaSO4 is left... umm from 0.0315mol of reactant... let me have a think..

Offline rannekk

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Re: problem regarding moles...
« Reply #3 on: June 26, 2007, 08:55:56 AM »
yes hahaaa its B.. 2 moles!. Cheers mate! Prob the easiest question ever, now that one looks at it  :o Thanks again!  ;D

Offline Borek

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Re: problem regarding moles...
« Reply #4 on: June 26, 2007, 09:23:56 AM »
from 0.0315mol of reactant...

Wrong here!
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Offline rannekk

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Re: problem regarding moles...
« Reply #5 on: June 26, 2007, 09:47:56 AM »
True... slip of mind.
its
CaSO4 + H2O  ->  CaSO4
0.0250mol    0.500mol    0.0250mol
      1        :       2      :       1

 :P


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