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### Topic: Dilutions  (Read 3614 times)

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##### Dilutions
« on: July 26, 2007, 04:34:05 AM »
Hi everybody,

If a solution A contains 100mg of quanine sulfate and it dissolved in 100ml of 0.5M of sulfuric acid and the second solution, solution B was made up by diluting 10ml of solution A using 0.5M sulfuric acid and made up 100ml, calculate the new concentration.

Using this value, solution C was made up by diluting 10ml of solution B and made it up to 25ml, calculate the new concentration for solution C.

Thank you
Disobedience is man's original virtue.It's through disobedience and rebellion that progress has been made.

#### sdekivit

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##### Re: Dilutions
« Reply #1 on: July 26, 2007, 04:43:24 AM »
first: 100 mg in 100 mL solution (= solution A): concentration = ?

--> then: solution B is 10 mL A to 100 mL solution: dilution factor = ? and use that to calculate the new concentration.

--> then: solution C = 10 mL B to 25 mL solution: dilution factor = ? --> concentration = ?

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##### Re: Dilutions
« Reply #2 on: July 26, 2007, 04:57:11 AM »
Sorry, but I meant using mol/L units

I tried this using C1V1=C2V2 formula and I ended up with 5M for concentration in solution A, 0.5M for solution B and 0.2M for solution C, please correct me if im wrong

Thank you
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#### AWK

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##### Re: Dilutions
« Reply #3 on: July 26, 2007, 05:05:30 AM »
solution B 100/10=10 times diluted
solution C 25/10 = 2.5 times
hence solution C is 25 times diluted with regards to solution A (you can use any units of concentration for solution A)
AWK