Is that correct?
Yo u ne.ed a 10mM solution of a p.otent (and dangerous) transcriptio.n inhibitor (mol wt 500) for experiment. To avoid handling the po.wder form of this c.ompound you decide to make up the whole bottle rather than attempt to weigh out a portion. The compound comes in 200mg batches. What volume would you add to one of these bottles to make up a 10mM solution?
My work so far: 10mM = 10mmol/L
Moles = mass/molarmass
So we have 200mg/500 = 2.5mmols (millimoles)
Not sure where to go from here.
Thanks for the help