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Offline rozannz

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NET ionic equation...
« on: August 13, 2007, 01:59:22 PM »
WRITE THE NET IONIC EQUATION FOR EACH OF THE REACTION AND NOTE THE VALUE OF DELTA H FOR EACH REACTION.

NaOH(s)---> Na+(aq) + OH-(aq) +x kJ

Na+(aq) + OH-(aq) + H+(aq) + Cl-(aq)---> H2O(I)+Na+(aq) + Cl-(aq) + x kJ

NaOH(s) + H+(aq) + Cl-(aq) ---> H2O(1)+Na+(aq) +Cl-(aq) +x kJ

Offline rozannz

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Re: NET ionic equation...
« Reply #1 on: August 13, 2007, 03:02:12 PM »
Equation #1 - write net ionic equation for dissolution of solid NaOH in water
Equation: NaOH (s) + H2O --> Na+ (aq) + OH- (aq) + H2O (l)
Net: NaOH (s) --> Na+ (aq) + OH- (aq)
deltaH = m * c * deltaT
deltaH = 200g * 1cal/moldegcel * 0.00418kj/cal * (13degcel)
deltaH = 10.868kJ



Equation #2 - write net ionic equation for aqueous soloutions of NaOH & HCl
Equation: NaOH (aq) + HCl (aq) ---> NaCl (aq) + H2O (l)
Net: OH- (aq) + H+ (aq) --> H2O (l)
deltaH = m * c * deltaT
deltaH = 200g * 1cal/moldegcel * 0.00418kJ/cal * (10degcel)
deltaH = -8.36kJ

Equation 3: Solid NaOH and aqueous HCl
Equation: NaOH (s) + HCl (aq) ---> NaCl (aq) + H2O
Net: OH- (s) + H+ (aq) --> H2O (l)
deltaH = m * c * deltaT


is that right???????????

Offline constant thinker

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Re: NET ionic equation...
« Reply #2 on: August 14, 2007, 08:52:10 PM »
Your net equations look fine to me.

I didn't double check the math, but the equation is right.
(∆H=m*c*∆T)
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Offline arunakms

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Re: NET ionic equation...
« Reply #3 on: August 21, 2007, 10:17:28 AM »
CaCO3 +2HNO3 gives Ca(NO3)2 +H2O+CO2

H2SO4(l) + Zn(aq) gives ZnSo4 +H2


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