Write an equation for the reaction with an excess of H2. Give all possible isomeric products.

I see the most obvious isomer adding a total of 6 H's (due to the equation) and getting rid of the double bonds but I don't understand how to get the other 3 isomers. I know that there are a total of 4 answers.

**Balanced equations and Mechanisms**

Create a balanced equation and write out the mechanism of the following reactions:

1) 1-octene, tested with Br2 in CH2Cl2

I got CH3(CH2)5CH=CH2 + Br2 ---> CH3(CH2)5CH2Br-CH2Br

Is this correct?

Would the mechanism just be a halogenation reaction?

2) n-heptane tested with Br2 in CH2Cl2, illuminating the Br2 solution.

I got C7H16 + Br* -----> C7H15Br + H*

* - electron

Is this correct?

Would the mechanism just be a free radical bromination and would it only be 2 steps resulting in the product of the balanced equation without the H*?

3) 1-octene tested with KMnO4

I got C8H16 + KMnO4 + H20 ----> C2H6O2 + C2H2O2 + MnO2

I do not feel that this is correct?

Is the mechanism just the 1-octene reacted with KMnO4/H2) to produce CH2OH-CH2OH resulting in further oxidation and ending up with CH2=O + CH2=O + MnO2?

4) Napthalene tested with AlCl3

I got C10H8 + CHCl3 ----> (C6H5)3CH + 3HCl

Is this correct? If so, how do I balance it?

I do not understand the mechanism for this reaction.

Please help and thank you for reading this. :Confuzzled: