1. No such thing as KSO_{4}

2. You are looking for side reaction - so your skeletal should not contain main product (HBr)

3. You have two weird coefficients - one is negative (all should be positive) one is zero (which means there is no SO_{2} in products, yet you were specifically told it IS present, so your equation doesn't describe the reaction in question).

What you were told is that side reaction is between KBr + H_{2}SO_{4} and it yields Br_{2} + SO_{2}:

KBr + H_{2}SO_{4} -> Br_{2} + SO_{2}

However, this can't be right for an obvious reason - no K and H on the right side. The most logical guess is that K becomes K_{2}SO_{4}. What about hydrogen? Hmm, that's more complicated, however, you have hydrogen and at the same time SO_{4}^{2-} gets converted to SO_{2} - so it looses oxygen. Hydrogen and oxygen means water, so your skeletal reaction should look like:

KBr + H_{2}SO_{4} -> Br_{2} + SO_{2} + K_{2}SO_{4} + H_{2}O

And you should balance it now.