I have been trying to do this book problem for hours and can't seem to figure it out. I know its simple but I just can't do it? Any help would be greatly appreciated.

**Indium Oxide contains 4.784g of indium for every 1.000g of oxygen. In 1869, when Mendeleev first presented his version of the periodic table, he proposed the formula In**_{2}O_{3} for Indium Oxide. Before that time, it was thought that the formula was InO. What values for the atomic mass of indium are obtained using these two formulas? Assume that oxygen has an atomic mass of 16.00.

The answers to this question are....

InO, atomic mass of In = 76.54

In_{2}O_{3}, atomic mass of In= 114.8

Can someone please show me how to do this problem. Thanks in advance.