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Topic: Calorimeter Problem  (Read 3626 times)

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Imrahil

  • Guest
Calorimeter Problem
« on: January 15, 2005, 02:52:45 PM »
I have this problem that I just cant do, I dont understand how to do it! Please help me find the answer!!! ok here it is.

When ice melts at 0 degrees celsius to form liquid water, it absorbs 334J/gram. The specific heat of water is 4.184 J/gc. Suppose the heat needed to melt a 35.0g ice cube is absorbed from water (210g) in a calorimeter at 21 degrees celsius. What is the final temp of water?

Apparently the answer is 6.6 degrees celsius.

Thanks

Demotivator

  • Guest
Re:Calorimeter Problem
« Reply #1 on: January 15, 2005, 10:17:55 PM »
35g(334j/g) = 210g(4.184j/gC)(21-T)

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