[Alpharius]

Well Ive been taken chem for 2 years now and i still dont understand how to do some basic stuff like stoichiometry XD....yeah its pretty bad, ive been attempting to do this one question for about 2 hours now and seeing as how i cant get it to work, i need whatever help i can get now.

 The problem says Calcium Hydroxide reacts with an aq solution of sodium carbonate to produce sodium hydroxide and calcium carbonate.

 So i balanced the equation and got Ca(OH)2+ Na2CO3 --> 2NaOH + CaCO3

 Assuming that i balanced it correctly and have the right formulas (which im also pretty bad at doing XD) the actual problem says
 
- What mass of sodium carbonate is needed to completely react with 175.0g of Calcium hydoxide.
    Im not sure how i am supose to solve for this....anyone think they can help?

[enahs]

175.0 g Calcium Hydroxide is how many mols?
For every mol of Calcium Hydroxide how many mols of sodium carbonate do you need?

[Alpharius]

175g of Ca(OH)2 is 74.093 g/mol so...2.36 mols.

So if 2.36 mols of Ca(OH)2 is suppose to be used up completely, i need x amount of Sodium Carbonate now. Hmmm...I'll see what I can do with that


EDIT: Okay, Im kinda slow at this....Can you explain how I can solve for how many mols are needed to react with sodium carbonate now knowing that i have 2.36 mols of Calcium hydoxide?

EDIT 2:  Nevermind, I figured it out on my own! Yay~ I feel smart now XD

 Thanks for the help

[constant thinker]

Always remember the term "mole ratios."