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Topic: Solution stoichiometry  (Read 8228 times)

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Offline govibe

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Solution stoichiometry
« on: September 26, 2007, 02:40:52 PM »
I'm having a bit of a problem with this...

1. "Douglasite is a mineral with the formula 2 KCl·FeCl2·2 H2O. Calculate the mass percent of douglasite in a 348.0 mg sample if it took 37.20 mL of a 0.1000 M AgNO3 solution to precipitate all of the Cl- as AgCl. Assume the douglasite is the only source of chloride ion."
Since this is a weird molecule, what would be the molecular equation of douglasite reacting with AgNO3? Does the coefficient of 2 distribute over the FeCl2 in addition to the KCl? I am able to find moles of AgNO3 but that is it...

Offline Borek

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Re: Solution stoichiometry
« Reply #1 on: September 26, 2007, 03:15:51 PM »
In the douglasite crystal there are two K+ per each Fe2+ - you may write it as (KCl)2FeCl2(H2O)2 (well, don't do that, but that's how it describes substance composition). Otherwise you just treat it as if it was one molecule.
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Offline govibe

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Re: Solution stoichiometry
« Reply #2 on: September 26, 2007, 05:27:17 PM »
so how do you figure out the equation when it reacts with the AgNO3?

Offline AWK

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Re: Solution stoichiometry
« Reply #3 on: September 27, 2007, 01:08:55 AM »
Write down a formula of douglasite, eq  as: K2FeCl3H4O2
and balace this reaction:
K2FeCl4H4O2 + AgNO3 = AgCl(s) + KNO3 + Fe(NO3)2 + H2O
AWK

Offline govibe

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Re: Solution stoichiometry
« Reply #4 on: September 27, 2007, 11:49:05 AM »
^How did you know to write the equation like that? (with the specific molecules)

Offline Borek

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Re: Solution stoichiometry
« Reply #5 on: September 27, 2007, 12:03:15 PM »
Observe anions and cations presnt - once you remove Ag+ and Cl- there are K+, Fe3+ and NO3- left - not much choice when it comes to decide what salts are present in the solution.

This question should be done with net ionic reaction, which you likely don't know yet.
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