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Topic: Complecated Limiting Reactant Problems!  (Read 9510 times)

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chemhuff

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Complecated Limiting Reactant Problems!
« on: January 20, 2005, 11:05:50 PM »
Hi...well, I sincerely say that I am NOT using this forum to get answers!  I've tried these problems a million times and can't understand them!  I know how to get the limiting reactant, its just the questions really confuse me!! >:(

1. I already balanced the equation:
Fe3O4 + 4H2 ---> 3Fe + 4H2O
Now here's the question: For the equation above, where 11.5g magnetic iron oxide is combined with .450 hydrogen gas, which substance is the limiting reactant?


I'M DUMBFOUNDED!!!! >:( ??? :-X
Here's the last one: (equation already balanced)
For the unbalance equation below, what mass of solid AgCl will precipitate from a solution of 1.50g CaCl2 with excess AgNO3?
CaCl2 + Ag NO3 ---> AgCl + Ca(NO3)2

PLEASE!  I SINCERELY ASK FOR *delete me*!  ...why do they have to make these questions confusing...urr

Offline Mitch

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Re:Complecated Limiting Reactant Problems!
« Reply #1 on: January 20, 2005, 11:13:23 PM »
Tell me how many moles of Iron Oxide you have. Then tell me how many moles of Hydrogen you have.
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chemhuff

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Re:Complecated Limiting Reactant Problems!
« Reply #2 on: January 20, 2005, 11:24:06 PM »
ok...forgive me if its wrong...i suck at this...for iron oxide, 27.82 mol (?) and for hydrogen 1.3 mol (?)  
I multiplied the atomic mass w/the number of atoms then divided it by one mole...is that wrong?

Offline Mitch

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Re:Complecated Limiting Reactant Problems!
« Reply #3 on: January 20, 2005, 11:32:44 PM »
Lets look at your units.

Atomic weight = grams / mol

# of atoms = (atoms)

moles = moles.

Now this is what you did, you multiplied (grams/mol) and (# of atoms) = grams*#atoms/moles

Then you divided by moles, so the units of that is = grams*#atoms/moles2

That doesn't give you the units of moles, try again.
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chemhuff

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Re:Complecated Limiting Reactant Problems!
« Reply #4 on: January 20, 2005, 11:44:27 PM »
ok....urr....is the mol for iron oxide 42.15?  and the mol for hydrogen 48.176?  1st, for iron oxide, I multiplied 3 atoms of iron times mole, then 4 atoms of oxygen times mole, and got a total of 42.15 mol for iron oxide.  Then I did the same for Hydrogen, 8 atoms*mole....GOD...i think i got it wrong again...

chemhuff

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Re:Complecated Limiting Reactant Problems!
« Reply #5 on: January 20, 2005, 11:53:43 PM »
NO WAIT!!  I think I got it this time....number of moles for iron oxide is 18.26, and number of moles for hydrogen is 1.32?

Offline Mitch

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Re:Complecated Limiting Reactant Problems!
« Reply #6 on: January 21, 2005, 12:27:50 AM »
moles of H2 is 0.225.
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chemhuff

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Re:Complecated Limiting Reactant Problems!
« Reply #7 on: January 21, 2005, 12:32:47 AM »
oh, ok...i calculated it wrong...sorry, I had to review the mole concept...so what do I do now?

Offline Mitch

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Re:Complecated Limiting Reactant Problems!
« Reply #8 on: January 21, 2005, 12:39:11 AM »
How many moles of Iron oxide do you have?
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chemhuff

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Re:Complecated Limiting Reactant Problems!
« Reply #9 on: January 21, 2005, 12:41:26 AM »
i said 18.26.....thats wrong?


chemhuff

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Re:Complecated Limiting Reactant Problems!
« Reply #10 on: January 21, 2005, 02:03:53 AM »
I got the answer!! With the help of Tiger....she amazingly tolerated my stupidity in Chemistry :)...the answer for the 1st question is Fe304!!  I'm still working on the second question!!

Offline Mitch

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Re:Complecated Limiting Reactant Problems!
« Reply #11 on: January 21, 2005, 02:30:28 AM »
Tiger should help you out on the board, so all can benefit. ;)
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Offline Donaldson Tan

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Re:Complecated Limiting Reactant Problems!
« Reply #12 on: January 21, 2005, 04:48:25 AM »
CaCl2 + 2AgNO3 -> 2AgCl + Ca(NO3)2

given excess silver nitrate added, you can safely assume all the chloride ions present is precipitated out as silver chloride.
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