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Topic: KOH and Mg(NO3)2  (Read 9221 times)

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Offline govibe

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KOH and Mg(NO3)2
« on: September 30, 2007, 07:58:28 PM »
100.0 mL aliquot of 0.200 M aqueous potassium hydroxide is mixed with 100.0 mL of 0.400 M aqueous magnesium nitrate.

For this equation: 2KOH (aq) + 1Mg(NO3)2 (aq) -> 1Mg(OH)2(s) + 2KNO3(aq)

Calculate the concentration of NO3- ion after precipitation is complete.

I first calculated the moles of KOH and Mg(NO3)2 and found that KOH was limited... what should I do next? will it matter that KOH is limiting reagent?
« Last Edit: September 30, 2007, 09:44:45 PM by govibe »
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Offline Bakegaku

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Re: KOH and Mg(NO3)2
« Reply #1 on: September 30, 2007, 11:05:04 PM »
Take a look at the state that the nitrate is in before and after the completion of the reaction and you may find you're doing more work than you want to.
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