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Topic: I have a question about a limiting reactant problem.  (Read 3440 times)

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Offline lardhaterplz

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I have a question about a limiting reactant problem.
« on: October 01, 2007, 09:38:57 PM »
Strontium chloride, SrCl2, reacts with sodium phosphate, Na3PO4 to form a precipitate according to the following reaction:

3 SrCl2 (aq)  +  2 Na3PO4 (aq)  ->  Sr3(PO4)2 (s)  +  6 NaCl(aq)
   
If 50.0 mL of 0.10 M SrCl2 is mixed with 50.0 mL or 0.10 M Na3PO4, how many grams of precipitate are formed?

ok, So I've set up the equation for the first part as:

?grams of Sr3(PO4)2 = 50 mL Na3PO4 x (1L/1000mL)(.10M Na3PO4/1 L Na3PO4)(163.94g Na3PO4/1 mol Na3PO4)(1 mol SrPO4/2 mol Na3PO4) = .40985 grams of SrPO4

Is this first part correct? I am studying for an exam tomorrow. Thank you so much!

Offline agrobert

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Re: I have a question about a limiting reactant problem.
« Reply #1 on: October 01, 2007, 10:09:10 PM »
How do you know if sodium phosphate is limiting?  If strontium chloride is limiting your answer is wrong.  Show the determination of the limiting reagent.
In the realm of scientific observation, luck is only granted to those who are prepared. -Louis Pasteur

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