Hi, I was planning on doing the gummy bear + KCLO3 reaction as a school demo, and was hoping someone could fill me in on exactly how this reaction works (with chemical equations hopefully).
As much as I understand, you melt the KCLO3 in a test tube (5g?) so that it dissociates in solution. When you add the gummy bear, what exactly happens? The oxygen from the chlorate react with the carbon in the gummy to form CO2, the gummy hydrogen and oxygen form H20 vapour, and not sure what else is formed (this is my understanding, correct me please if I'm wrong). The reaction is exothermic so it continues to fuel the release of O2 from the chlorate to continue the reaction until the gummy is consumed.
I'm just hoping someone can correct me, and expand on what happens, as well as show a chemical equation as I really don't know how this will work out.
The dissociation with the bunsen burner will work out to be? 2KCLO3(s) -> 2KCL(aq) + 3O2(g) ?
Then I don't know what the equation with the gummy will be.
Any help would be greatly appreciated, thanks guys/gals.