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Topic: Mass in g from Moles  (Read 2820 times)

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Offline achibaby1974

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Mass in g from Moles
« on: February 08, 2008, 02:44:02 PM »
Ok. Online HW says

Calculate each of the following:

f.) mass in grams of .57 mol KMnO4
Okay so I start out with .57 mol.

.57 mol KMnO4 (158.04 g KMnO4/ 1 mol KMnO4) = 90.0828

I put 90 , 90.08 and 90.1 and they're all wrong. It says check significant figures. WHY? 


Offline Borek

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Re: Mass in g from Moles
« Reply #1 on: February 08, 2008, 03:14:46 PM »
90 should be OK, no idea why it is rejected.
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