[jonnyset]

What is the pH of the solution which results from mixing 25 mL of 0.30 M HF (aq) and 25 mL of 0.30 M NaOH (aq) at 25 0 C? (Ka of HF = 7.2 x 10-4)
    (o) 8.16
    (_) 12.02
    (_) 8.31
    (_) 10.86
    (_) 5.84

I think what you're supposed to do is find the limiting reagent, determine the excess reactant and that will determine the pH. I tried, but I'm not getting the answer. I have several problems like this, but I think they're based on the same concept. Please help...then I'll be able to do the rest. Thanks a lot!

[enahs]

You have a weak acid and therefor a buffer solution. Familiar?

[AWK]

You have a weak acid and therefor a buffer solution. Familiar?

This time this is a hydrolysis of salt!

[jonnyset]

if I do my calculations for hydrolysis of a salt, I get the very close, but different answer choice answer ( C )
What am i doing wrong?

[jonnyset]

gahh nvm
ok I gots it
thanks

[AWK]

Which concentration did you use - 0.15 M ? (0.15 is correct) and pH 8.16

[enahs]

I think I got my post crossed! I suck, sorry about that jonnyset.

Less tabbed browsing for me!