[psychfan29]

2SO2 (g) + O2 (g) ===> 2SO3 (g)

SO2 (g)   *delta*H (kJ/mol) = -296.1
O2 (g)     "                     " = 0
SO3 (g)   "                     " =  -395.2

What volume, in liters, of SO3 (g) would be produced at 20.0 degrees Celsius and 1.00 atm of pressure in the above combustion reaction involving the transfer of 50.00 kJ of heat?

I'm not sure how to start.  Can I solve using dimensional analysis?  Or is there a formula that I can use?   

[Dan]

(note: D = delta)

1. Determine DH for the reaction. Hint: see Hess's law

2. You now know the heat (kJ) transfer involved for the production of 1 mol of sulfur trioxide. If you transfer 50 kJ heat how many moles of sulfur trioxide do you get? Let's call this X mol

3. Assuming an ideal gas, what volume does X mol of the gas occupy. Hint pV = nRT for an ideal gas