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### Topic: Solution/product calculation help  (Read 9341 times)

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#### Kris44

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##### Re: Solution/product calculation help
« Reply #15 on: November 04, 2007, 02:59:36 PM »
Ok i understand. I have just started studying moles etc so am still getting my head around it .

I have another question that i have attempted but am not sure if i'm correct.

What volume of hydrochloric acid of concentration 2.00mol dm3 would have to be added to 25.0cm3 of 0.500mol dm3 sodium carbonate to give a neutral solution of sodium chloride?

Heres what i have done.

I worked out equation to be Na2CO3 + 2HCL ---->2NaCl + CO2+H2O

So 1mole neutralises 2moles of acid?
HCL con =2.00mol dm3
moles of sodium carbonate= 25.0x0.5/1000 = 1.25^-2
=1.25x10^-2 x 2 =0.025=2.5x10^-2
moles of acid =VM/1000
=V=moles x 1000/M = 12.5cm3??

This is probably completely wrong but i have had a go.

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