Ok i understand. I have just started studying moles etc so am still getting my head around it
I have another question that i have attempted but am not sure if i'm correct.
What volume of hydrochloric acid of concentration 2.00mol dm3
would have to be added to 25.0cm3
of 0.500mol dm3
sodium carbonate to give a neutral solution of sodium chloride?
Heres what i have done.
I worked out equation to be Na2
+ 2HCL ---->2NaCl + CO2
So 1mole neutralises 2moles of acid?
HCL con =2.00mol dm3
moles of sodium carbonate= 25.0x0.5/1000 = 1.25^-2
=1.25x10^-2 x 2 =0.025=2.5x10^-2
moles of acid =VM/1000
=V=moles x 1000/M = 12.5cm3
This is probably completely wrong but i have had a go.