Hey I just had a quick question any help/ advise would be really appreciated. The question is as follows... Acetylene, C_{2}H_{2} and hydrofluoride react to give difluoroethane, C_{2}H_{4}F_{2}. When 1.0 mol of C_{2}H_{2} and 5.0 mol of HF reacted in a 10.0 L flask, how many mols difluoroethane will be produced?

I balanced the equation: C_{2}H_{2} + 2HF --> C_{2}H_{4}F_{2}

Now since there is only one mol of C_{2}H_{2} I thought that it was the limiting reactant and therefore using the molar ratios from the balanced equation 1.0 mols difluoroethane would be produced. I was told this was wrong however and for the life of me I can't figure out how else you would do this... again any advice or hint as to where to start would be much appreciated.