Hey I just had a quick question any help/ advise would be really appreciated. The question is as follows... Acetylene, C2H2 and hydrofluoride react to give difluoroethane, C2H4F2. When 1.0 mol of C2H2 and 5.0 mol of HF reacted in a 10.0 L flask, how many mols difluoroethane will be produced?
I balanced the equation: C2H2 + 2HF --> C2H4F2
Now since there is only one mol of C2H2 I thought that it was the limiting reactant and therefore using the molar ratios from the balanced equation 1.0 mols difluoroethane would be produced. I was told this was wrong however and for the life of me I can't figure out how else you would do this... again any advice or hint as to where to start would be much appreciated.