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Topic: Balancing a Redox Equation  (Read 4451 times)

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supradedupra

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Balancing a Redox Equation
« on: February 06, 2005, 02:07:01 AM »
here is the problem:



I followed an example in the book and got the following:

CrI3+ 11 Cl2+ 32 OH -> CrO4+ 3 IO4 + 16 H2O + 22 Cl

But, when I try to submit the answer (32 L) it tells me that it is incorrect.  I am truly stumped.  I have asked just about everyone I am in contact with and they all look at my work and see that i have balanced the equation, so they don't understand what I have done wrong.

I used the Half-Reaction method to get that answer.  Please help

Offline Mitch

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Re:Balancing a Redox Equation
« Reply #1 on: February 06, 2005, 03:11:38 AM »
Your charges aren't even balanced. ::)
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supradedupra

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Re:Balancing a Redox Equation
« Reply #2 on: February 06, 2005, 04:06:07 AM »
I reworked it backwards and I found that I had put my chlorine as having a charge of 1e- instead of 2e-. which gave me half an answer...

I went back and put 64L in and it was correct. So I came back and you also found my flaw... thank you very much :)


Thanks for your help :)

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