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Topic: calculating moles of NaOH in 300ml of .1 NaOH & calculating volume  (Read 5221 times)

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Bekah

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calculating moles of NaOH in 300ml of .1 NaOH & calculating volume
« on: November 16, 2007, 12:10:10 AM »
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Two questions: Calculate the number of moles of NaOH in 300ml of .1 M NaOH.

2nd question: Calculate the volume of 3 M NaOH required to prepare 300ml of .1 M NaOH

I have a few of these types of questions and not sure how to do them. Hoping an answer to these will help me get started.

The number of moles in NaOH is: Na=23+O=16+H=1 which totals 40 moles
That is all I know how to do...

Sev

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Re: calculating moles of NaOH in 300ml of .1 NaOH & calculating volume
« Reply #1 on: November 16, 2007, 12:23:37 AM »
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Two questions: Calculate the number of moles of NaOH in 300ml of .1 M NaOH.

If you have 0.3L, and there are 0.1moles per L, how many moles? n=cv

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2nd question: Calculate the volume of 3 M NaOH required to prepare 300ml of .1 M NaOH

How many moles in the 300mL soln (same as first question).  This amount will also be present in 3M soln.  c1v1 = c2v2: solve for v2.

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The number of moles in NaOH is: Na=23+O=16+H=1 which totals 40 moles
That is all I know how to do...

You have calculated the molar mass of NaOH here, which is not nessesary to solve problem.

Bekah

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Re: calculating moles of NaOH in 300ml of .1 NaOH & calculating volume
« Reply #2 on: November 16, 2007, 01:33:12 AM »
What does c & v stand for in the equation?

Sev

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Re: calculating moles of NaOH in 300ml of .1 NaOH & calculating volume
« Reply #3 on: November 16, 2007, 01:44:11 AM »
c is concentration (in moles/Litre), v is volume (in Litres), n is number of moles.