[importfan878]

1. A watersoluble prolblem of gold and chlorine is treated with silver nitrate to convert the chlorine to compleately to silver cholorida,AgCl. In an experiment 328mg of the compound gave 464 mg of silver chloride. Calculate persentage of Cl in the compound. What is emperical formula?

The anwsers gven are 35.0% CL and AuCl^3(Gold III Chloride_

I must show all work and anwser how to do prolbem. Thanks

[LQ43]

so can you show any work?

[importfan878]

I got the equation

AuCl3 + 3AgNO3 = 3AgCl + Au(NO3)3

[LQ43]

that is a correct equation but I think you need to show how the empirical formula of AuCl3 is determined, which is why the first question is what is the % of Cl in the compound. Using 464 mg of the silver chloride would be a start. How many grams of chlorine here?

[importfan878]

i Think i was able to do it but i didnt need anything but the aucl3. I found the percent composition of cl to be 35% and AU 65%. Then i converted to moles and divided by small number coming up with 1 and 3. Not sure of name of this method. BUt i didnt need all the other number it gave me or the rest of prolblem. Did i do what its asking?

[LQ43]

what you did was find % composition using just the formula of AuCl3. That is not what the question is asking you to do.

The steps to find empirical formula are:

1. what are the elements in the compound
2. what is the mass in g of each element
3. find the moles of each element
4. divide by the smallest # of moles to get the smallest whole number ratio

I think you are on step 2
- use the 464 mg of AgCl, can you find how many gram of Cl is there?
- this many grams of Cl was in the original 328 mg of the gold chloride compound, how many grams of gold?

...

[importfan878]

Yeah I did those steps and got Aucl3. COnfused on what else it is asking me to do. What i think you referred to as step 2. I found there was 114.608 mg of Cl in the result. and i found there was 213.396 g of gold in aucl3 but i dont see where its asking this. Thanks alot dude

[LQ43]

114.608 mg of Cl ;  213.396 g of gold in aucl3

use these numbers for step 3

then do step 4 , yes it gives you the AuCl3 answer.

i dont see where its asking this.

These are parts of the process of determining empirical formula which is what the question asked. Usually the question does not give you the answer (as you first showed for information). Pretend you did not have the answer AuCl3 - the original problem statement did not give this

1. A watersoluble prolblem of gold and chlorine is treated with silver nitrate to convert the chlorine to compleately to silver cholorida,AgCl. In an experiment 328mg of the compound gave 464 mg of silver chloride. Calculate persentage of Cl in the compound. What is emperical formula?

,

Knowing the answer helps you to confirm that you did the problem correctly but the question wants you to show how the answer is determined, that is, do all the steps

Thanks alot dude

no problem, but I'm not a "dude" 

[importfan878]

thanks i got it