Ok, so I'm working on some homework, and the problem says:
A sample of gas occupies a volume of 9.50L at 0.968 atm and 28 degrees Celsius.
a). Calculate the pressure of the gas if its volume is decreased to 4.89L while its temperature is held constant.
b). At what temperature in degrees Celsius is the volume of the gas 4.00L if the pressure is kept constant?
So, I'm thinking that I need to use the forumula (P1*V1)/T1 = (P2*V2)/T2, but I'm not positive. What are your thoughts?
EDIT: I did a using that formula and ended up getting:
(.968)(9.50)(301.15)/(301.15)(4.89) = 1.88057 atm
and for b, I got:
(.968)(4.00)(301.15)/(.968)(9.5) = 126.8 degrees Kelvin
But it asks for Celsius, so I got 126.8 - 273.15 = -146.35 degrees Celsius