March 29, 2024, 06:12:19 AM
Forum Rules: Read This Before Posting


Topic: reduction agents  (Read 3153 times)

0 Members and 1 Guest are viewing this topic.

Offline googleviet

  • Regular Member
  • ***
  • Posts: 13
  • Mole Snacks: +0/-0
reduction agents
« on: December 24, 2007, 08:29:56 PM »
 I want to reduce C=N to CNNH but I don't have enough money to buy reductive reagents (e.g. LiALH4, NaBH4, NaCNBH3,...). Is there any way to prepare them in laboratory. Or is there any way to reduce with cheaper reagents.

Offline Rabn

  • Chemist
  • Full Member
  • *
  • Posts: 284
  • Mole Snacks: +28/-13
Re: reduction agents
« Reply #1 on: December 24, 2007, 09:56:38 PM »
Can you be more specific what your reagent and desired product is? I.e.  starting with H2CN, HCN etc...

Offline googleviet

  • Regular Member
  • ***
  • Posts: 13
  • Mole Snacks: +0/-0
Re: reduction agents
« Reply #2 on: December 25, 2007, 09:31:00 AM »
my topic is the transition -C=O -> -C-NH2  -> -CONH-R. I try to find out the best procedure with cheap reagents, especially reductive reagents. The keyword may be reduction amination. Can I prepare LiAlH4 or NaBH4 in my lab?Maybe I have to search on internet first?

Offline Mitch

  • General Chemist
  • Administrator
  • Sr. Member
  • *
  • Posts: 5298
  • Mole Snacks: +376/-3
  • Gender: Male
  • "I bring you peace." -Mr. Burns
    • Chemistry Blog
Re: reduction agents
« Reply #3 on: December 25, 2007, 12:03:00 PM »
Those reagents are already rather cheap.
Most Common Suggestions I Make on the Forums.
1. Start by writing a balanced chemical equation.
2. Don't confuse thermodynamic stability with chemical reactivity.
3. Forum Supports LaTex

Sponsored Links