ok, i have a lab due and i know THIS IS not cheating just looking for help.

this is what i got.

Mass of labeled Beaker 50.29g

Mass of beaker + zinc 51.18g

Mass of beaker + zinc chloride 52.14g

Mass of beaker + zinc chloride(2nd trial) 52.14g

Calculations:

1a. Calculate the mass of zinc that reacted. Include descriptions with this calculation.

Mass of labeled beaker +zinc – mass of the labeled beaker.

51.18g – 50.39g= .89g of zinc

b. Calculate the number of moles of zinc.

(Zinc)=(1 mole)

1 Mole of zinc

(.89g)= ( 1 mole)=0.0136 = 0.014

1 65.4

2.) Calculate the mass of zinc cloride that was produced. Include descriptions with this calculation.

Mass of beaker + zinc chloride- Mass of beaker + zinc

52.14g – 51.18g=0.96g

3a) Calculate the mass of chlorine in the zinc chloride. Include descriptions with this calculation.

Mass of Zinc Chloride- mass of Zinc= Mass of chlorine

0.96-.89=0.07g of chlorine

3b) Calculate the number of moles of chlorine.

(0.07)=(1 mole)=0.002g

1 35.45

4.) Determine the ratio: Moles Cl. This ratio should be close to a whole number.

Moles Zn

---0.002g=0.14

0.014