[wils0645]

I have a solution with 30% albumin (300 mg/ml), 0.85% NaCl (8.5 mg/ml) and 69.15% H2O.  I want to dilute with 0.9% NaCl to make a 100 mL solution.  My desired composition is 0.03% albumin, 0.85-0.9% NaCl, 99.07-99.12% H2O.  How much out of each solution should I take out and mix?

[AWK]

Show your attempt.

[wils0645]

If I have a 100 mL solution, 30 mg albumin is 0.03%.  850 mg NaCl is 0.85%.  100 mL H2O is 99.12%.  My problem is I'm trying to figure out with diluting with 0.9% saline instead of water.  That's what I'm confused about.  I don't believe I can use the eq. C1V1 = C2V2 can I?

(300 mg/mL) (?) = (0.3 mg/mL) (100 mL).  (?) = 0.1 mL or 100 uL.  So I would mix 99.9 mL NaCl, 0.1 mL albumin solution?  Thanks for the help.

[AWK]

Good job

[wils0645]

That's right?  I surprise myself.