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You are given: 12 g HCl + 18g CaCO31. Write out your reaction equation: CaCO3 + HCl → CaCl2 + CO2 + H2O2. Balance your reaction equation: CaCO3 + 2HCl → CaCl2 + CO2 + H2O 3. Remember that species react mole to mole and NOT gram to gram.4. Then you use your balanced reaction equation and find the grams of calcite left upon the completion of the reaction. Which means UNREACTED or EXCESS calcite (calcium carbonate).
You have 12 g HCl How many moles are this? And with how much calcite can it react?
Quote from: Kryolith on January 20, 2008, 03:50:49 PMYou have 12 g HCl How many moles are this? And with how much calcite can it react?I thought 1 mole of a compound was the relative molecular mass, in grams?
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