Hi, I'm having a difficult time with with problem, I'm wondering if someone could give me some tips?

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A student prepares a solution of carbonate-free NaOH. Upon performing a rough titration, the student finds the concentration to be 0.0638 M instead of 0.1000 M. Assuming that the volume of the solution is 950.0 mL, how many grams of sodium hydroxide should be added to the solution to produce a concentration as close as possible the desired 0.1000 M? (Assume that the sodium hydroxide is carbonate-free.)

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I would really appreciate any help.

Here is what I know. I'm pretty sure that I'm suppose to use M1V1 = M2V2, but I don't know what I could solve for in the M2V2 because the volume and Molarity of product has already been given? I know that I'm looking at this problem wrong though.

Thanks a lot