We have some problems concerning calculation percentage of NaOH and % of Al. This method includes NaF (it liberates alkalinity bounded by aluminium).
The calculation goes (2P1 - 1/3 P2 - m) * 0,04 = NaOH %, P1, P2 and m are parameters.
Is this what they meant?
((2P1 - 1)/(3 P2 - m)) * 0,04 = NaOH %???
And does anybody knows whats the maximum concentration of Aluminium in caustic? After which concentration does not increase in solution no mater how much do you add Al.