What [OH-] should be maintained in a solution if, after precipitation of Mg+2 as
Mg(OH)2, the remaining Mg+2 is to be at a level of 1 microgram Mg2+ / L?
Ksp = 1.8x10^-11.
I found the initial concentration of OH- to be
After I did stoicheometry I foud that 1 microgram Mg2+ / L is tantamount to 4.11x10^-8 moles.
What exactly do I do with this result? Am I supposed to add it to the initial [OH-]
that's what I did and I didn't get the right answer. According to the book, the answer should be 0.02M.