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Topic: Redox Titration -Determine the % of Iron II and Iron III  (Read 7195 times)

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Offline xXAznGirlXx

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Redox Titration -Determine the % of Iron II and Iron III
« on: February 19, 2008, 02:19:38 PM »
determine the % of iron II and iron III in a mixture containing both, where i am given 200cm3 of a solution containing 1.3g of iron ions(Fe 2+ Fe 3+) using potassium magnanete.
I wrote down the equation already, and method, but i don't know how to work out the % from it :/
Can you please help or any ideas how to start?
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Offline JGK

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Re: Redox Titration -Determine the % of Iron II and Iron III
« Reply #1 on: February 19, 2008, 02:45:01 PM »
Titrating an aliquot of your sample with the potassium manganate will allow you to determine the concentration of Iron (II) in the sample, if you know that and the total iron in the sample the rest is easy.  8)
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Offline xXAznGirlXx

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Re: Redox Titration -Determine the % of Iron II and Iron III
« Reply #2 on: February 19, 2008, 06:05:45 PM »
oh ok thanks alot!!
So once I found out the concentration , do i find the % from that?
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Offline LQ43

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Re: Redox Titration -Determine the % of Iron II and Iron III
« Reply #3 on: February 19, 2008, 09:41:30 PM »
If you have concentration of the Fe2+ion and know the volume of your aliquot, you can get mol of Fe2+, then calculate gms Fe2+.

mass Fe2+/volume aliquot =  total mass of Fe2+/200cm3 sample


total mass Fe2+/ 1.3g  = %

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Offline xXAznGirlXx

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Re: Redox Titration -Determine the % of Iron II and Iron III
« Reply #4 on: February 20, 2008, 09:02:28 AM »
ohh yeah thanks :) sorry but what is gms?
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Offline JGK

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Re: Redox Titration -Determine the % of Iron II and Iron III
« Reply #5 on: February 20, 2008, 09:50:23 AM »
gms = grams = g  :-\
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