C6H5COOH + NAOH = C6H5COONA+ + H20
Close - although it is... not balanced. For the reaction to be balanced not only atoms must be balanced, but also the charge. In your case there is +1 on the right. (Not to be nitpicky about NA instead of Na).
So the correct version is
C
6H
5COOH + NaOH -> C
6H
5COONa + H
2O
It gives the same ratio 1:1.
Its a 1;1 ratio. However we were stuck after this stage. We attemepted the % question but we were getting ridiciolous values like 168%. Can someone take me through how to do it please.
Have you not forgot about your blank? Your solutions contains not only benzoic acid, but also phosphoric buffer. This buffer is nothing else but a mixture of phosphoric acid and some base - but acid is in a excess. So when neutralizing your solution you have to neutralize BOTH benzoic acid and phosphoric acid from the buffer. Blank titration should tell you how much phosphoric acid was in your sample - you should substract this amount from the results of the sample titration.