see im totally useless
You are not. You were close. You just needed a small push.
Anyway when [NH2-NH2]e = [NH3+NH2]e (so would the equilibrium concentrations be exactly the same) i.e. pH is 5.77.
Not sure if I like your notation. And once again - you are close, but you need a push. This is base, and you are given pKb, not pKa. 5.77 is slightly acidic - not a thing that sounds logical in the case of base solution. Think it over - have you found pH or pOH?
And when [NH3+-NH2]e = [NH3+-NH3+]e then the pH of the solution is 15.05.
You have used the same logic that you used in the previous question - so you are wrong in exactly the same way. However, there is more - this logic in water doesn't extend so far. Water is much stronger base and it is present in excess. Don't bother with pH of this solution if you don't have to, just ignore it for now.