I'm having a little trouble understanding Acid Base Equilibrium, its probably from the fact that I didn't fully understand regular Equilibrium. Ive asked my teacher and some fellow students to try to help me understand but the way they explain it just doesn't work for me. Heres an example of the stuff I'm just not understanding:
Calculate the pH change produced by adding .1moles of solid NaOH to 500 ml of 1.00M HC2H3O2 and 1.00M NaC2H3O2
HC2H3O2->H+ + C2H3O2-
So we have 1mol/.5L=2
Ka = 1.8x10-5
1.8x10-5=[H+][C2H3O2-]/[HC2H3O2]
1.8x10-5=x(2+.1)/(2-.1)
x= 1.62x10-5 which makes the pH 4.78
Now i just flip the signs for the NaC2H3O2 so its:
1.8x10-5=x(2-.1)/(2+.1)
x=1.98x10-5 which makes the pH 4.70
But when I looked at the answer it says I should've got a pH of 4.75 and 4.92 to give me a difference of .18, but I only got a difference of .08