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Topic: Kc  (Read 3540 times)

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Offline timchai

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Kc
« on: March 06, 2009, 07:30:14 AM »
(iii)        Sketch, on the graph in (i), the curves you would expect if the experiment was
        repeated in an identical manner, except that
                (1)        the temperature was 40 oC,
The ans said part 1 . I think it is wrong . the curve max should be lower , bcoz the reaction is exothermic, so Kp affect, By …Law , Kp decrase , so max , yield should lower
reaction is decomposition of H2O2

http://uwants.com/attachment.php?aid=4665433&nothumb=yes

Offline Astrokel

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Re: Kc
« Reply #1 on: March 06, 2009, 10:31:13 AM »
Could you post the whole question here? I have alot of question marks.
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline Astrokel

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Re: Kc
« Reply #2 on: March 06, 2009, 07:22:04 PM »
Quote
idecomposition of H2O2 to form O2 , this is the origimal curve , now ask u wt happen to ... when temp .increase , ans said 1 , i think wrong as if affect Kc as i said , can u reead my ans , plz help me to solve bcoz it appae r in F5 mock, i remember , i now F7, so i think in the past , i hv poor concept ...

The reaction is not in equilibrium!
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

Offline Astrokel

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Re: Kc
« Reply #3 on: March 06, 2009, 09:27:59 PM »
Post your questions here so others could help and learn.

Quote
how about it is N2 and H2 to NH3
then do u remember in F5 textbook, we always say that  increase temp , the max yield unchange
so ithink in F.7 , we know the concept is wrong .plz help me to correct my concept

Correct, if there is an equilibrium system, any increasing or decreasing temperature will affect both rates and product yield.

Read this: http://www.chemguide.co.uk/physical/equilibria/haber.html#top
No matters what results are waiting for us, it's nothing but the DESTINY!!!!!!!!!!!!

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