June 16, 2024, 07:51:19 PM
Forum Rules: Read This Before Posting

### Topic: Please calculate the number of mols of oxygen gas produced per second  (Read 65396 times)

0 Members and 1 Guest are viewing this topic.

#### Frederick95

• Regular Member
• Posts: 82
• Mole Snacks: +0/-12
##### Re: Please calculate the number of mols of oxygen gas produced per second
« Reply #75 on: March 18, 2008, 07:42:10 PM »
Let me rewrite the question in a neat order

The question was:
Calculate the change in hydrogen peroxide concentration per second.  This is the rate.  (Hint:  What volume of liquid does the hydrogen peroxide now occupy?).

The reaction was:
Reaction   Volume of 6% H2O2 (mL) 8.0
Volume of distilled water (mL) 2.0
Volume of 1.0 M NaI (mL) 10.0
Volume of distilled water (mL) 0.0
O2 production in 60 s (mL) 93.0

2 H2O2 --> 2 H2O + O2

Since you have helped me solve mass for H2O2, I can now find number of moles for H2O2 by using finding molarity.

Molarity = moles of solute (H2O2) / litres of solution (0.01 L)

gives me value of M

but what is next?

#### diplomat65

• New Member
• Posts: 3
• Mole Snacks: +0/-2
##### Re: Please calculate the number of mols of oxygen gas produced per second
« Reply #76 on: March 19, 2008, 12:27:03 AM »
To Frederick, please i need some help with this rates lab

Thank you

I appreciate it

#### Frederick95

• Regular Member
• Posts: 82
• Mole Snacks: +0/-12
##### Re: Please calculate the number of mols of oxygen gas produced per second
« Reply #77 on: March 19, 2008, 12:32:11 AM »
The results of this discussion are incorrect

#### diplomat65

• New Member
• Posts: 3
• Mole Snacks: +0/-2
##### Re: Please calculate the number of mols of oxygen gas produced per second
« Reply #78 on: March 19, 2008, 02:01:31 AM »
please someone, i need some help with the rates lab

thank you very much

#### mo_1984

• Regular Member
• Posts: 11
• Mole Snacks: +0/-3
##### Re: Please calculate the number of mols of oxygen gas produced per second
« Reply #79 on: March 19, 2008, 09:48:17 PM »
Sorry Arkcon, I forgot
Since 1ml=1cm3

151 mL = 151 cm^3

I beleive I now rearrange the Ideal Gas Law to find # of mols?

n = PV / RT

=(102.6 kPa)(151 cm^3) / (8.3145 J/mol K)(290 K)

= 15492.6 / 2411.205

= 6.4 mols

where did u get 8.3145 j/mol k from???