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Topic: What is the value for k (in L/(mol s))?  (Read 8193 times)

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Offline Nathaniel

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What is the value for k (in L/(mol s))?
« on: March 15, 2008, 10:38:01 PM »
A reaction has a rate r = k[ B]^2. When 2.73 mol of B are present in 4.50 L container and the reaction begins, the initial rate is 8.62 mol/(L s). What is the value for k (in L/(mol s)?


Heres how I answered it

k = 8.62/ L s (4.50 L/ 7.4529)

=5.17 L/(mol s)?

but the correct answer is 23. 4L/(mol s)?
« Last Edit: March 16, 2008, 04:48:26 AM by Borek »

Offline Yggdrasil

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Re: What is the value for k (in L/(mol s))?
« Reply #1 on: March 16, 2008, 12:44:22 PM »
[ B] should be squared.

Offline Marcus Soutlo

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Re: What is the value for k (in L/(mol s))?
« Reply #2 on: March 22, 2008, 11:28:41 AM »
I did [ B]2 already to get 7.4529 (look above)
« Last Edit: March 22, 2008, 11:30:04 AM by Borek »

Offline Yggdrasil

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Re: What is the value for k (in L/(mol s))?
« Reply #3 on: March 22, 2008, 12:28:31 PM »
[B ] = moles of B/volume = 2.73mol/4.50L

You need to square both the numerator and the denominator.

Offline Marcus Soutlo

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Re: What is the value for k (in L/(mol s))?
« Reply #4 on: March 22, 2008, 01:01:32 PM »
[B ] = moles of B/volume = 2.73mol/4.50L

      = 2.73^2 / 4.50^2

      =7.4529 / 20.25

      = 0.3679

What is my next step?

Thanks again

Offline Padfoot

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Re: What is the value for k (in L/(mol s))?
« Reply #5 on: March 23, 2008, 10:07:26 PM »
solve for k.

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