[Wil"]

Consider the following cell diagram
Zn(s)｜Zn²⁺(0.10M)｜｜Zn²⁺(1.0M)｜Zn(s)

The half-reactions are
Oxidation: Zn(s)-->Zn2+(0.1M)+2e^-
Reduction:Zn²⁺(1.0M)+2e^- -->Zn(s)

The overall reaction is
Zn²⁺(1.0M) -->Zn²⁺(0.10M)


Question
From the overall equation, does that mean only the Zn²⁺ in the 1.0M
compartment will change grafually its concentration to 0.10M??

Then how about the diluted compartment with 0.1M Zn²⁺?? will the concentration also be changed?