u r right and u can calculate Electrode potential: Delta G^o= -nFE^o

First Calculate delta G^o using the data which i am sure is giving to u in your book. then use the equation to solve for E^o.

gud luck...

Okay, I found out that was wrong. You can't find the Gibbs energy for an electron anyway

Instead, I thought about combining different half cell reactions.

I found this:

2 H2SO3 + 4 e- + 2 H+ <--> S2O3^2- + 3 H2O

E^o = 0.40 V

SO4^2- + 4 H+ + 2 e- <--> H2SO3 + H2O

E^o = 0.158 V

So if I combine these, I end up with something like

S2O3^2- + 5 H2O <--> SO4^2- + 8 e- + 10 H+

(I reverse both and multiplied the last one with 2).

Does this seem ok? The question now is - how do I calculate E^o for this reaction?