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Topic: I need some help with Molarity and solutions cna some one help ASAP  (Read 14076 times)

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Offline CStrike18

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this is the question i am having trouble on  can anyone help?

Q:Iron(III)chloride can be produced by reacting Iron(III)oxide with hydrochloric acid. how many millimeters of a 6.00M HCl solution are needed to produce 3.25g of Iron(III)chloride?

A: i have no worldly idea of where to even start ..help
« Last Edit: March 30, 2008, 05:39:43 PM by CStrike18 »

Offline chrisbb

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #1 on: March 30, 2008, 05:11:56 PM »
How about something simple: a reaction equation? :)

Fe2O3  + HCl --> ?

Offline CStrike18

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #2 on: March 30, 2008, 05:18:11 PM »
Fe2O3 +6HCl --> 2FeCl3 + 3H2O   (I think)

Offline chrisbb

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #3 on: March 30, 2008, 05:22:24 PM »
LOL!
I missread that!

You are correct!
OK, so now we have the correct formula, what is the next item you can find? If you are stuck in a question what is the first thing you can try and find (other than the rxn equation)?

Offline Arkcon

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #4 on: March 30, 2008, 05:33:08 PM »
Fe2O3 +6HCl --> 2FeCl3 + 3H2O   (I think)

Great, now, the units of a chemical equation are moles.  You've been given a quantity of HCl in molarity and product in grams, you'll have to convert  the units.
Hey, I'm not judging.  I just like to shoot straight.  I'm a man of science.

Offline CStrike18

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #5 on: March 30, 2008, 05:38:43 PM »
do i convert the 3.25g into moles then plug that and the 6.00M HCl in the Molarity equation?

Offline enahs

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #6 on: March 30, 2008, 05:42:59 PM »
How many mols of the Iron compound do you have?

If you have that many mols, according to you balanced equation, how many mols of HCl is required? How many mL of HCl at the given molarity is required to have that many mols of HCl?


Offline CStrike18

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #7 on: March 30, 2008, 05:45:50 PM »
Molarity = amount of solute divided by the volume of the solvent

 i have the Molarity but i dont have either of the amount or the volume so thats where i am stuck

Offline enahs

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #8 on: March 30, 2008, 05:50:59 PM »
Molarity = amount of solute divided by the volume of the solvent

Correct.

Irrelevant, but correct.

How many molEs of Iron(III) Chloride do you have? It is a solid, it is not a molarity, just the number of molEs.

So let us pretend you have 1 molE of Iron(III) Chloride. According to your balanced chemical equation, how many molEs of HCl are required? What volume of 6M HCl supplies that number of molEs?

Now, do the same thing, but with your data.

Offline CStrike18

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #9 on: March 30, 2008, 05:57:01 PM »
to make 2 moles of FeCl3 i need 6 moles of HCl... or do i take the 3.25g of FeCl3 and convert it to Moles?

Offline enahs

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #10 on: March 30, 2008, 06:12:34 PM »
to make 2 moles of FeCl3 i need 6 moles of HCl... or do i take the 3.25g of FeCl3 and convert it to Moles?

Yes.

How many mol's of FeCl3 do you have? How many mols of HCl are required to completely react with that amount of FeCl?

Offline CStrike18

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #11 on: March 30, 2008, 06:16:29 PM »
converting 3.25g of FeCl3 gives me .02 mols of FeCl3

Offline enahs

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #12 on: March 30, 2008, 06:21:18 PM »
Good. So if you have 0.02 mols of FeCl3, how many mols of HCl were required?

What volume of 6M HCl supplies that amount of mols?

Offline CStrike18

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #13 on: March 30, 2008, 06:25:42 PM »
i dont remember how to do that  ???
but once i have the moles of it i can convert from moles to volume but then i need the density of HCl right?

Offline Borek

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Re: I need some help with Molarity and solutions cna some one help ASAP
« Reply #14 on: March 30, 2008, 06:28:47 PM »
to convert from moles to volume i need the density of HCl right?

No, density is necessary when converting between molarity and percent concentrations. There is no need for density here.

Write down formula of molar concentration and solve it for volume.
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