I still do not have the clear understanding how to solve this kind of problem:
32 g of water is heated from ice at -5 degrees C to water at 0 degrees. How much heat is absorbed?
We need to find q1 and q2 and add them together.
1. q1 = c(ice) x m (mass) x delta T ; q1 = 2.03 x 32 x 5 = 324.8 J
2. As it is water at 0 degrees, we need to use H fus, which is 6.01 KJ/m. This is the part I think I made the mistake before. As it is 6.01 KJ per mole, I need to convert 32 g of H2O into moles,32 / (2+16) = 1.78 mol
q2 = 6.01 x 1.78 = 10.69 J
q total = 324.8 + 10.69 = 335.49 J
Please check and explain if I am doing it wrong. Thank you.