Can any one help me with this question as i am completly confused.
A person’s blood alcohol (C2H5OH) level can be determined by
titrating a sample of blood plasma with a potassium dichromate
solution. The balanced equation is:
16H+(aq) + 2Cr2O72- (aq) + C2H5OH(aq) → 4Cr3+(aq) + 2CO2(g) + 11H2O(l)
If 35.46 mL of 0.05961 M Cr2O7 2− is required to titrate 28.00 g of
plasma, what is the mass percent of alcohol in the blood?