hey guys..

i have a very similar assignment, and i've been stuck on this part below for over 2 hours now. Could anyone explain this to me.

calculate the solubility product for calcium hydroxide?

Ksp = [Ca+2][OH-1]2

You should have an average value for the amount of H+ that you put into solution.

For every 2 Mol of HCl added you neutralize one mol of CaOH2 right?

Take the number of mol of hydroxide neutralized and divide by the volume of solution this will give you molarity of the CaOH2.

You know from the stoichiometry that there is 2 times as much OH- present as calcium.

So.. plug these numbers into the equation for the Ksp and you should arrive at your answer.

Ksp = [molarity of OH- / 2 ][molarity of OH-]2

I may have gotten myself side tracked in the math, but if someone else can varify, I believe that is a correct way to reach the answer.