A 5.00-g mixture of zinc and aluminum reacted with HCL to give 1.278 x 10^2 ounces of hydrogen at 7.16 x 10^1 °F and 1.013 bar pressure. Th unbalance reactions are:
(a) Zn + HCl ---> ZnCl2 + H2
(b) Al + HCl ---> AlCl3 + H2
When balanced, the coefficients of reactants and products are:
(a) Zn + 2HCl --> ZnCl2 + H2
(b) 2Al + 6 HCl ---> 2AlCl3 + 3H2
Ok, this is where I have no CLUE....
(c) Calculate the percent by mass of zinc in the original mixture.
Now the hint that was given to me....I still have not clue
Hint -- % by mass zinc = mass of zinc/mass of mixture.
Maybe I am all chem out ...right now.... HELP?
OK.. UPDATE 4/23/2004. I think I have the answer to (c)
%Zn = 65.37/0.076 x 100 = 0.116 Zn
%Al = 26.98/0.041 x 100 = 0.151 Al
Can anyone check this for me and let me know if I am correct?