[mnuslt]

question:

Explain how the Mg to O ratio would have been affected if you failed to convert all of the Mg3N2 present to magnesium oxide. I am sorry but I do not even understand what the question is asking , so that I can answer it. All I can figure out is that it is asking me, if I did not completely burn the Mg until I got a constant mass how would that change the Mg to O ratio. It would increase the oxygen ratio maybe? I do not know?

[AWK]

You will get a mixture of MgO and Mg3N2.

[srchn4ansrs]

The ratio will be affected by how much of both substances remain. For example... if the original ration was 2:5 and you had a 90% total combustion rate...
2 x .90 = 1.80 and 5 x .90 = 4.5. New ratio (remaining product, assuming both of the original reactants were equally consumed in the reaction) = 0.2:0.5. This also is based only on consumption of reactant and completely discounts any formation of product via the reaction. You didn't provide the actual ration so I am just laying out an example for you.

Srchn