May 07, 2021, 08:52:26 PM
Forum Rules: Read This Before Posting


Topic: Equilibrium question: *delete me*  (Read 3093 times)

0 Members and 1 Guest are viewing this topic.

xyxtem

  • Guest
Equilibrium question: *delete me*
« on: March 30, 2005, 11:28:48 PM »
I have a hard time when doing this question. My teacher sent back the question to me and asked me to do the correction. However, none of my friends got it right and my teacher refused to give us the answer. Please help me out.

The pH of 0.010M carbonic acid solution, H2CO3, is 4.17 at 25oC. Calculate the value of the dissociation constant, Ka, at this temperature.

Offline AWK

  • Retired Staff
  • Sr. Member
  • *
  • Posts: 7984
  • Mole Snacks: +555/-93
  • Gender: Male
Re:Equilibrium question: *delete me*
« Reply #1 on: March 31, 2005, 01:24:15 AM »
Though carbonic acid ia a weak dibasic one, for this calculation you can neglect the second ionization constant. Then
Ka=[H+]^2/c_H2CO3
This should give you about 4.6x10^-7
AWK

Sponsored Links